Question

The radius of $A{g}^{+}$ ion is $126pm$ and $I^{-}$ ion is $216pm$ . The co-ordination number of $A{g}^{+}$ ion is:-

• A. $2$
• B. $4$
• C. $6$
• D. $8$

Answer 1

Answer: (C)

$L.R.R=\frac{r^{+}}{r^{-}}=\frac{126}{216}=0.58$