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Chemistry
The radius of Ag+ ion is 126pm and I- ion is 216pm . The co-ordination number of Ag+ ion is:-
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Q. The radius of $Ag^{+}$ ion is $126pm$ and $I^{-}$ ion is $216pm$ . The co-ordination number of $Ag^{+}$ ion is:-
NTA Abhyas
NTA Abhyas 2020
A
$2$
B
$4$
C
$6$
D
$8$
Solution:
$L.R.R=\frac{r^{+}}{r^{-}}=\frac{126}{216}=0.58$