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Q. The radius of $Ag^{+}$ ion is $126pm$ and $I^{-}$ ion is $216pm$ . The co-ordination number of $Ag^{+}$ ion is:-

NTA AbhyasNTA Abhyas 2020

Solution:

$L.R.R=\frac{r^{+}}{r^{-}}=\frac{126}{216}=0.58$