Question

The radius of a ball is $(5.4\pm 0.2)cm.$ The percentage error in the volume of the ball is

• A. $11\%$
• B. $4\%$
• C. $7\%$
• D. $9\%$

Answer 1

Answer: (A)

Percentage error in the volume of the ball
$=3\frac{\Delta r}{r}\times 100=3\times \frac{0.2}{5.4}\times 100=\frac{200}{18}=11\%$