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  4. The radius of a ball is (5.4 ± 0.2) cm . The percentage error in the volume of the ball is

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Q. The radius of a ball is $(5.4 \pm 0.2) cm .$ The percentage error in the volume of the ball is

Physical World, Units and Measurements

Solution:

Percentage error in the volume of the ball
$=3 \frac{\Delta r}{r} \times 100=3 \times \frac{0.2}{5.4} \times 100=\frac{200}{18}=11 \%$