Question

The radius of 2nd Bohr's orbit of hydrogen atom is:

• A. $0.053nm$
• B. $0.106nm$
• C. $0.2116nm$
• D. $0.4256nm$

Answer 1

Answer: (C)

Second Bohr orbit of hydrogen atom, i.e., $n=2$.

Atomic number of hydrogen $(z)=1$

by using

$r=\frac{0.529n^2}{Z}=\frac{0.529\times (2{)}^2}{1}$

$=2.116A^{\circ }=0.2116nm$