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Q. The radius of 2nd Bohr's orbit of hydrogen atom is:

Structure of Atom

Solution:

Second Bohr orbit of hydrogen atom, i.e., $n =2$.

Atomic number of hydrogen $(z)=1$

by using

$r =\frac{0.529 n ^{2}}{ Z }=\frac{0.529 \times(2)^{2}}{1}$

$=2.116 A ^{\circ}=0.2116\, nm$