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Chemistry
The radius of 2nd Bohr's orbit of hydrogen atom is:
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Q. The radius of 2nd Bohr's orbit of hydrogen atom is:
Structure of Atom
A
$0.053\, nm$
B
$0.106\, nm$
C
$0.2116\, nm$
D
$0.4256\, nm$
Solution:
Second Bohr orbit of hydrogen atom, i.e., $n =2$.
Atomic number of hydrogen $(z)=1$
by using
$r =\frac{0.529 n ^{2}}{ Z }=\frac{0.529 \times(2)^{2}}{1}$
$=2.116 A ^{\circ}=0.2116\, nm$