The quantum number of four electrons are given below - I. n = 4, l = 2, ml = -2, ms = - 1/2 II. n = 3, l = 2, ml = 1, ms = + 1/2 III. n = 4, l = 1, ml = 0, ms = + 1/2 IV. n = 3, l = 1, ml = 1, ms = - 1/2 The correct order of their increasing energies will be -

Question

The quantum number of four electrons are given below - I. n = 4, l = 2, ml = -2, ms = - 1/2 II. n = 3, l = 2, ml = 1, ms = + 1/2 III. n = 4, l = 1, ml = 0, ms = + 1/2 IV. n = 3, l = 1, ml = 1, ms = - 1/2 The correct order of their increasing energies will be - (A) IV < III < II < I (B) IV < II < III < I (C) I < II < III < IV (D) I < III < II < IV

Tardigrade Admin · Accepted Answer

According to (n + ℓ ) rule: 3p < 3d < 4p < 4d

Q. The quantum number of four electrons are given below -
I. $n = 4, l = 2, m_{l} = - 2, m_{s} = - 1/2$
II. $n = 3, l = 2, m_{l} = 1, m_{s} = + 1/2$
III. $n = 4, l = 1, m_{l} = 0, m_{s} = + 1/2$
IV. $n = 3, l = 1, m_{l} = 1, m_{s} = - 1/2$
The correct order of their increasing energies will be -

IV < III < II < I

IV < II < III < I

I < II < III < IV

I < III < II < IV

According to $(n + ℓ)$ rule : 3p < 3d < 4p < 4d

Q. The quantum number of four electrons are given below - I. n=4,l=2,ml​=−2,ms​=−1/2 II. n=3,l=2,ml​=1,ms​=+1/2 III. n=4,l=1,ml​=0,ms​=+1/2 IV. n=3,l=1,ml​=1,ms​=−1/2 The correct order of their increasing energies will be -