1. Tardigrade
  2. Question
  3. Chemistry
  4. The quantum number of four electrons are given below - I. n = 4, l = 2, ml = -2, ms = - 1/2 II. n = 3, l = 2, ml = 1, ms = + 1/2 III. n = 4, l = 1, ml = 0, ms = + 1/2 IV. n = 3, l = 1, ml = 1, ms = - 1/2 The correct order of their increasing energies will be -

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Q. The quantum number of four electrons are given below -
I. $n = 4, l = 2, m_l = -2, m_s = - 1/2$
II. $n = 3, l = 2, m_l = 1, m_s = + 1/2$
III. $n = 4, l = 1, m_l = 0, m_s = + 1/2$
IV. $n = 3, l = 1, m_l = 1, m_s = - 1/2$
The correct order of their increasing energies will be -

JEE MainJEE Main 2019Structure of Atom

Solution:

According to $(n + \ell )$ rule : 3p < 3d < 4p < 4d