The product of acid hydrolysis of P and Q can distinguished by

Question

The product of acid hydrolysis of P and Q can distinguished by <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/b8e122adf3e1bd0a4874c4ea3dd98459-.png" /> (A) Lucas Reagent (B) 2 ,4-DNP (C) Fehling’s Solution (D) NaHSO3

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/bc41c3420941a0abe202d13ff34f73fd-.png" /> Acidic hydrolysis of esters gives acid and alcohol as alcohol obtained undergoes keto-enol tautomerism so from P we get ketone and from Q we get aldehyde. Ketone (non-reducing) and aldehyde (reducing) can be distinguished by Fehling solution.

Q. The product of acid hydrolysis of $P$ and $Q$ can distinguished by

Lucas Reagent

$2, 4 - D NP$

Fehling’s Solution

$N a H S O_{3}$

Acidic hydrolysis of esters gives acid and alcohol as alcohol obtained undergoes keto-enol tautomerism so from $P$ we get ketone and from $Q$ we get aldehyde. Ketone (non-reducing) and aldehyde (reducing) can be distinguished by Fehling solution.

Q. The product of acid hydrolysis of P and Q can distinguished by

Lucas Reagent

2,4−DNP

Fehling’s Solution

NaHSO3​

Acidic hydrolysis of esters gives acid and alcohol as alcohol obtained undergoes keto-enol tautomerism so from P we get ketone and from Q we get aldehyde. Ketone (non-reducing) and aldehyde (reducing) can be distinguished by Fehling solution.

Q. The product of acid hydrolysis of $P$ and $Q$ can distinguished by

$2, 4 - D NP$

$N a H S O_{3}$

Acidic hydrolysis of esters gives acid and alcohol as alcohol obtained undergoes keto-enol tautomerism so from $P$ we get ketone and from $Q$ we get aldehyde. Ketone (non-reducing) and aldehyde (reducing) can be distinguished by Fehling solution.