Question

The probability that a leap year selected at random contains $53$ Sunday is

• A. $\frac{7}{366}$
• B. $\frac{28}{183}$
• C. $\frac{1}{7}$
• D. $\frac{2}{7}$

Answer 1

Answer: (D)

A leap year has $366$ days in which $52$ weak and two days are extra
i.e., (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday)
So probability that a leap year contains $53$ Sundays $=2/7$