Question

The probability that a leap year selected at random contains $ 53 $ Sunday is

• A. $ \frac{7}{366} $
• B. $ \frac{28}{183} $
• C. $ \frac{1}{7} $
• D. $ \frac{2}{7} $

Answer 1

Answer: (D)

A leap year has $366$ days in which $52$ weak and two days are extra
i.e., (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday)
So probability that a leap year contains $53$ Sundays $=2/7$