Question

The probability distribution curve for $2s$ electron appears like

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

(a) is correct answer because $R^2$ is always +ve and there is one node in $2s$ -orbital.

(b) is not possible because there is no node and this graph is for $1s$ -orbital.

(c) is possible if we plot $r$ with $4\pi r^2{R}^2$ for $2s$ -orbital.

(d) is not possible because $R^2$ cannot be negative. It is obtained when ' $r$ ' is plotted with ' $R$ ' for $2s$ -orbital.