Question

The pressure of a moist gas at $27^{\circ }C$ is $4$ atm. The volume of the container is doubled at the same temperature. The new pressure of the moist gas is $\dots .\times 10^{-1}atm$. (Nearest integer) (Given : The vapour pressure of water at $27^{\circ }C$ is $0.4atm$ )

Answer 1

Answer: 22

${\left[P_{gas}\right]}_0+\text{ V.P. }=4$
${\left[P_{gas}\right]}_0=4-0.4=3.6$
As volume is doubled, ${\left[P_{gas}\right]}_{\text{new }}=1.8atm$
New Total Pressure $=1.8+0.4=2.2atm$