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  4. The pressure of a moist gas at 27° C is 4 atm. The volume of the container is doubled at the same temperature. The new pressure of the moist gas is ldots . × 10-1 atm. (Nearest integer) (Given: The vapour pressure of water at 27° C is 0.4 atm )

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Q. The pressure of a moist gas at $27^{\circ} C$ is $4$ atm. The volume of the container is doubled at the same temperature. The new pressure of the moist gas is $\ldots . \times 10^{-1} atm$. (Nearest integer) (Given : The vapour pressure of water at $27^{\circ} C$ is $0.4\, atm$ )

JEE MainJEE Main 2022States of Matter

Solution:

$ {\left[ P _{ gas }\right]_0+\text { V.P. }=4}$
$ {\left[ P _{ gas }\right]_0=4-0.4=3.6}$
As volume is doubled, $\left[ P _{ gas }\right]_{\text {new }}=1.8\, atm$
New Total Pressure $=1.8+0.4=2.2 a\,tm$