Question

The power dissipated in the circuit shown in the figure is $25$ watts. The value of $R$ is :-

• A. $10\Omega$
• B. $30\Omega$
• C. $20\Omega$
• D. $15\Omega$

Answer 1

Answer: (C)

$P=\frac{(10{)}^2}{5}+\frac{(10{)}^2}{R}=25$ watt
$\Rightarrow R=\frac{(10{)}^2}{5}=20\Omega$