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Q. The power dissipated in the circuit shown in the figure is $25$ watts. The value of $R$ is :-Physics Question Image

Current Electricity

Solution:

$P =\frac{(10)^{2}}{5}+\frac{(10)^{2}}{ R }=25$ watt
$\Rightarrow R =\frac{(10)^{2}}{5}=20\, \Omega$