The potential energy of the electron present in the ground state of Li2 + ion is represented by

Question

The potential energy of the electron present in the ground state of Li2 + ion is represented by (A) +(3 e2/4 π ϵ 0 r) (B) -(3 e/4 π ϵ 0 r) (C) -(3 e2/4 π ϵ 0 r2) (D) -(3 e2/4 π ϵ 0 r)

Tardigrade Admin · Accepted Answer

Potential energy of the electron present in ground state is given as Potential energy =(- Z e2/4 π ϵ 0 r)=-(3 e2/4 π ϵ 0 r)

Q. The potential energy of the electron present in the ground state of $L i^{2 +}$ ion is represented by

$+ \frac{3 e ^{2}}{4 π ϵ _{0} r}$

$- \frac{3 e}{4 π ϵ _{0} r}$

$- \frac{3 e ^{2}}{4 π ϵ _{0} r ^{2}}$

$- \frac{3 e ^{2}}{4 π ϵ _{0} r}$

Potential energy of the electron present in ground state is given as

Potential energy $= \frac{- Z e ^{2}}{4 π ϵ _{0} r} = - \frac{3 e ^{2}}{4 π ϵ _{0} r}$

Q. The potential energy of the electron present in the ground state of Li2+ ion is represented by

+4πϵ0​r3e2​

−4πϵ0​r3e​

−4πϵ0​r23e2​

−4πϵ0​r3e2​