Question

The potential energy of the electron present in the ground state of $Li^{2 +}$ ion is represented by

• A. $+\frac{3 e^{2}}{4 \pi \epsilon _{0} r}$
• B. $-\frac{3 e}{4 \pi \epsilon _{0} r}$
• C. $-\frac{3 e^{2}}{4 \pi \epsilon _{0} r^{2}}$
• D. $-\frac{3 e^{2}}{4 \pi \epsilon _{0} r}$

Answer 1

Answer: (D)

Potential energy of the electron present in ground state is given as

Potential energy $=\frac{- Z e^{2}}{4 \pi \epsilon _{0} r}=-\frac{3 e^{2}}{4 \pi \epsilon _{0} r}$