Question

The potential drop across the $3\Omega$ resistor is

• A. 1 V
• B. 1.5 V
• C. 2 V
• D. 3 V

Answer 1

Answer: (A)

Equivalent resistance, $R=4+\frac{3\times 6}{3+6}=6\Omega$
and main current $i=\frac{E}{R}=\frac{3}{6}=0.5A$
Now potential difference across the combination of
$3\Omega$ and $6\Omega ,V=0.5\times \left(\frac{3\times 6}{3+6}\right)=1V$
The same potential difference also develops across $3\Omega$ resistance.