Thank you for reporting, we will resolve it shortly
Q.
The potential drop across the $3\, \Omega$ resistor is
Current Electricity
Solution:
Equivalent resistance, $R=4+\frac{3 \times 6}{3+6}=6 \,\Omega$
and main current $i=\frac{E}{R}=\frac{3}{6}=0.5\, A$
Now potential difference across the combination of
$3\, \Omega$ and $6\, \Omega, V=0.5 \times\left(\frac{3 \times 6}{3+6}\right)=1 V$
The same potential difference also develops across $3 \,\Omega$ resistance.
