The potential difference between two parallel plates is 104V . If the plates are separated by 0.5 cm, the force on an electron between the plates is

Question

The potential difference between two parallel plates is 104V . If the plates are separated by 0.5 cm, the force on an electron between the plates is (A)  32× 10-13N  (B)  0.32× 10-13N  (C)  0.032× 10-13N  (D)  3.2× 10-13N

Tardigrade Admin · Accepted Answer

The force F=(eV/d) =(1.6× 10-19× 104/0.5× 10-2)=3.2× 10-13N

Q. The potential difference between two parallel plates is $10^{4} V$ . If the plates are separated by 0.5 cm, the force on an electron between the plates is

$32 \times 10^{- 13} N$

$0.32 \times 10^{- 13} N$

$0.032 \times 10^{- 13} N$

$3.2 \times 10^{- 13} N$

The force $F = \frac{e V}{d}$ $= \frac{1.6 \times 10 ^{- 19} \times 10 ^{4}}{0.5 \times 10 ^{- 2}} = 3.2 \times 10^{- 13} N$

Q. The potential difference between two parallel plates is 104V . If the plates are separated by 0.5 cm, the force on an electron between the plates is

32×10−13N

0.32×10−13N

0.032×10−13N

3.2×10−13N