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Q. The potential difference between two parallel plates is $ {{10}^{4}}V $ . If the plates are separated by 0.5 cm, the force on an electron between the plates is

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Solution:

The force $ F=\frac{eV}{d} $ $ =\frac{1.6\times {{10}^{-19}}\times {{10}^{4}}}{0.5\times {{10}^{-2}}}=3.2\times {{10}^{-13}}N $