The point at which the circles x2 + y2 - 4x - 4y + 7 = 0 and x2 + y2 - 12x - 10y + 45 = 0 touch each other is

Question

The point at which the circles x2 + y2 - 4x - 4y + 7 = 0 and x2 + y2 - 12x - 10y + 45 = 0 touch each other is (A) ((13/5),(14/5)) (B) ((2/5),(5/6)) (C) ((14/5),(13/5)) (D) ((2/5),2+(√21/6))

Tardigrade Admin · Accepted Answer

Correct answer is (c) ((14/5),(13/5))

Q. The point at which the circles $x^{2} + y^{2} - 4 x - 4 y + 7 = 0$ and $x^{2} + y^{2} - 12 x - 10 y + 45 = 0$ touch each other is

$(\frac{13}{5}, \frac{14}{5})$

$(\frac{2}{5}, \frac{5}{6})$

$(\frac{14}{5}, \frac{13}{5})$

$(\frac{2}{5}, 2 + \frac{21}{6})$

Correct answer is (c) $(\frac{14}{5}, \frac{13}{5})$

Q. The point at which the circles x2+y2−4x−4y+7=0 and x2+y2−12x−10y+45=0 touch each other is

(513​,514​)

(52​,65​)

(514​,513​)

(52​,2+621​​)