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Q. The point at which the circles $x^2 + y^2 - 4x - 4y + 7 = 0$ and $x^2 + y^2 - 12x - 10y + 45 = 0$ touch each other is

Conic Sections

Solution:

Correct answer is (c) $\left(\frac{14}{5},\frac{13}{5}\right)$