The plot of log k vs 1 / T helps to calculate

Question

The plot of log k vs 1 / T helps to calculate (A) The energy of activation (B) The rate constant of the reaction (C) The order of the reaction (D) The energy of activations as well as the frequency factor

Tardigrade Admin · Accepted Answer

According to Arrhenius equation log k= log A-(E a /2.303) ⋅ (1/T) Plot of log k vs (1/T) is a straight line <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/abf4ee674b9c6ab528f50cdbe737d653-.png" /> Slope =-(E a /2.303 R) Intercept = log A

Q. The plot of $lo g k$ vs $1/ T$ helps to calculate

The energy of activation

The rate constant of the reaction

The order of the reaction

The energy of activations as well as the frequency factor

According to Arrhenius equation
$lo g k = lo g A - \frac{E _{a}}{2.303} \cdot \frac{1}{T}$
Plot of $lo g k v s \frac{1}{T}$ is a straight line

Slope $= - \frac{E _{a}}{2.303 R}$
Intercept $= lo g A$

Q. The plot of logk vs 1/T helps to calculate