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Q.
The plot of $\log k$ vs $1 / T$ helps to calculate
Chemical Kinetics
Solution:
According to Arrhenius equation
$\log k=\log A-\frac{E_{ a }}{2.303} \cdot \frac{1}{T}$
Plot of $\log k vs \frac{1}{T}$ is a straight line
Slope $=-\frac{E_{ a }}{2.303 R}$
Intercept $=\log A$
