Question

The pH of a 0.02 M solution of $HCl$ is

• A. 2.2
• B. 2.0
• C. 0.3
• D. 1.7

Answer 1

Answer: (D)

$0.02MHCl=2\times {10}^{-2}MHCl$ $[H^{+}]=2\times {10}^{-2}$ $pH=-\log [H^{+}]$ $=-\log [2\times {10}^{-2}]$ $=-\log 2+2\log 10$ $=-0.3010+2$ $=1.7$