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Q. The pH of a 0.02 M solution of $ HCl $ is

MGIMS WardhaMGIMS Wardha 2007

Solution:

$ 0.02\,M\,HCl=2\times {{10}^{-2}}M\,HCl $ $ [{{H}^{+}}]=2\times {{10}^{-2}} $ $ pH=-\log [{{H}^{+}}] $ $ =-\log [2\times {{10}^{-2}}] $ $ =-\log 2+2\log 10 $ $ =-0.3010+2 $ $ =1.7 $