The pH of 0.1 M aqueous ammonia (Kb=1.8× 10-5) is

Question

The pH of 0.1 M aqueous ammonia (Kb=1.8× 10-5) is (A) 9.13 (B) 10.13 (C) 11.13 (D) 12.13

Tardigrade Admin · Accepted Answer

The aqueous solution of ammonia is basic in nature. ∴ [OH-]=√Kb× C =√1.8× 10-5× 0.1 =1.341× 10-3 pOH=- log [OH-] =- log [1.341× 10-3] =2.87 pH=14-pOH =14-2.87=11.13

Q. The pH of 0.1 M aqueous ammonia $(K_{b} = 1.8 \times 10^{- 5})$ is

9.13

10.13

11.13

12.13

The aqueous solution of ammonia is basic in nature. $∴$ $[O H^{-}] = K_{b} \times C$ $= 1.8 \times 10^{- 5} \times 0.1$ $= 1.341 \times 10^{- 3}$ $pO H = - lo g [O H^{-}]$ $= - lo g [1.341 \times 10^{- 3}]$ $= 2.87$ $p H = 14 - pO H$ $= 14 - 2.87 = 11.13$

Q. The pH of 0.1 M aqueous ammonia (Kb​=1.8×10−5) is