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  4. The pH of 0.1 M aqueous ammonia (Kb=1.8× 10-5) is

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Q. The pH of 0.1 M aqueous ammonia $ ({{K}_{b}}=1.8\times {{10}^{-5}}) $ is

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Solution:

The aqueous solution of ammonia is basic in nature. $ \therefore $ $ [O{{H}^{-}}]=\sqrt{{{K}_{b}}\times C} $ $ =\sqrt{1.8\times {{10}^{-5}}\times 0.1} $ $ =1.341\times {{10}^{-3}} $ $ pOH=-\log [O{{H}^{-}}] $ $ =-\log [1.341\times {{10}^{-3}}] $ $ =2.87 $ $ pH=14-pOH $ $ =14-2.87=11.13 $