Q. The pH of $0.01 M K O H$ is

13558 188 COMEDKCOMEDK 2010Equilibrium Report Error

A

2

16%

B

8

15%

C

14

14%

D

12

55%

Solution:

$pO H = - l o g [O H^{-}] = - l o g (0.01) = 2$
$p H + pO H = 14$
$p H = 14 - pO H = 14 - 2 = 12$