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  4. The pH of 0.01 M KOH is

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Q. The pH of $0.01\, M\, KOH$ is

COMEDKCOMEDK 2010Equilibrium

Solution:

$pOH = - log[OH^{-}] = - log(0.01) = 2$
$pH + pOH = 14$
$pH = 14 - pOH = 14 - 2 = 12$