Question

The periodic table consists of 18 groups. An isotope of copper, on bombardment with protons, undergoes a nuclear reaction yielding element $X$ as shown below. To which group, element $X$ belongs in the periodic table?
${}_{29}^{63}Cu+{}_1^{1}H\to 6_0^{1}n+\alpha +2{}_1^{1}H+X$

Answer 1

Answer: 8

${}_{29}^{63}Cu+{}_1{H}^1\to 6{}_0{n}^1+{}_2^{4}He+2{}_1{H}^1+{}_z^{A}X$

Mass number: $63+1=1\times 6+4+1\times 2+A$

$A=64-12=52$

Atomic number: $29+1=6\times 0+2+2\times 1+Z$

$Z=30-4=26$

${}_z^{A}X={}_{26}^{52}Fe$

Hence $X$ is in group ' 8 ' in the periodic table.