The period of the function y= sin 2 ω t is

Question

The period of the function y= sin 2 ω t is (A) (π/4 ω) (B) (π/2 ω) (C) (π/ω) (D) (2 π/ω)

Tardigrade Admin · Accepted Answer

sin 2 ω t=((1/2)-(1/2) cos 2 ω t) This is function having periodicity T=(2 π/2 ω)=(π/ω) It represents a SHM with point of equilibrium occurring at (1/2) instead of zero

Q. The period of the function $y = sin^{2} ω t$ is

$\frac{π}{4 ω}$

$\frac{π}{2 ω}$

$\frac{π}{ω}$

$\frac{2 π}{ω}$

$sin^{2} ω t = (\frac{1}{2} - \frac{1}{2} cos 2 ω t)$
This is function having periodicity $T = \frac{2 π}{2 ω} = \frac{π}{ω}$
It represents a SHM with point of equilibrium occurring at $\frac{1}{2}$ instead of zero

Q. The period of the function y=sin2ωt is

4ωπ​

2ωπ​

ωπ​

ω2π​