Question

The period of the function $y=\sin ^{2} \,\omega t$ is

• A. $\frac{\pi}{4 \omega}$
• B. $\frac{\pi}{2 \omega}$
• C. $\frac{\pi}{\omega}$
• D. $\frac{2 \pi}{\omega}$

Answer 1

Answer: (C)

$\sin ^{2} \omega t=\left(\frac{1}{2}-\frac{1}{2} \cos 2 \omega t\right)$
This is function having periodicity $T=\frac{2 \pi}{2 \omega}=\frac{\pi}{\omega} $
It represents a SHM with point of equilibrium occurring at $\frac{1}{2}$ instead of zero