Question

The period of ${\sin }^2\theta$ is :

• A. ${\pi }^2$
• B. $\pi$
• C. $2\pi$
• D. $\pi /2$

Answer 1

Answer: (B)

Key Idea : Period of $\sin \theta$ and $\cos \theta$ is $2\pi$
Since, ${\sin }^2\theta =\frac{1-\cos 2\theta }{2}=\frac{1}{2}-\frac{1}{2}\cos 2\theta$
$\therefore$ Period of ${\sin }^2\theta =\frac{2\pi }{2}=\pi$