Question

The period of $\sin ^{2} \theta$ is :

• A. $\pi^{2}$
• B. $\pi$
• C. $2 \pi$
• D. $\pi / 2$

Answer 1

Answer: (B)

Key Idea : Period of $\sin \theta$ and $\cos \theta$ is $2 \pi$
Since, $\sin ^{2} \theta=\frac{1-\cos 2 \theta}{2}=\frac{1}{2}-\frac{1}{2} \cos 2 \theta$
$\therefore $ Period of $\sin ^{2} \theta=\frac{2 \pi}{2}=\pi$