The peak value of an alternating e.m.f. E=E0 sin ω t is 10 volt and its frequency is 50 Hz. At a time t=(1/600 s ), the instantaneous value of the e.m.f. is

Question

The peak value of an alternating e.m.f. E=E0 sin ω t is 10 volt and its frequency is 50 Hz. At a time t=(1/600 s ), the instantaneous value of the e.m.f. is (A) 1 volt (B) 5 √3 volt (C) 5 volt (D) 10 volt

Tardigrade Admin · Accepted Answer

E=E0 sin ω t, E0=10 V v=50 Hz , t=(1/600) E=10 sin (2 π) × 50 × (1/600) =10 sin (π/6)=10((1/2)) =5 volt

Q. The peak value of an alternating e.m.f. $E = E_{0} sin ω t$ is $10$ volt and its frequency is $50 Hz$ . At a time $t = \frac{1}{600 s}$ , the instantaneous value of the e.m.f. is

$1$ volt

$53$ volt

$5$ volt

$10$ volt

$E = E_{0} sin ω t,$
$E_{0} = 10 V$
$v = 50 Hz,$
$t = \frac{1}{600}$
$E = 10 sin (2 π) \times 50 \times \frac{1}{600}$
$= 10 sin \frac{π}{6} = 10 (\frac{1}{2})$
$= 5$ volt

Q. The peak value of an alternating e.m.f. E=E0​sinωt is 10 volt and its frequency is 50Hz. At a time t=600s1​, the instantaneous value of the e.m.f. is

1 volt

53​ volt

5 volt

10 volt