Question

The peak value of alternating current is $5\sqrt{2}$ ampere. The mean square value of current will be :

• A. 5 A
• B. 2.5 A
• C. $5\sqrt{2}$
• D. none of these

Answer 1

Answer: (A)

Here: $I_0=5\sqrt{2}A$
Root mean square value of current
$I_{rms}=\frac{I_0}{\sqrt{2}}\frac{5\sqrt{2}}{\sqrt{2}}=5A$