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  4. The peak value of alternating current is 5√2 ampere. The mean square value of current will be :

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Q. The peak value of alternating current is $ 5\sqrt{2} $ ampere. The mean square value of current will be :

JIPMERJIPMER 2004

Solution:

Here: $I_{0}=5 \sqrt{2} A$
Root mean square value of current
$I_{ rms}=\frac{I_{0}}{\sqrt{2}} \frac{5 \sqrt{2}}{\sqrt{2}}=5\, A$