The particle executing simple harmonic motion has a kinetic energy K0 cos2 ω t .The maximum values of the potential energy and the total energy are respectively

Question

The particle executing simple harmonic motion has a kinetic energy K0 cos2 ω t .The maximum values of the potential energy and the total energy are respectively (A)  K0 / 2 and K0 (B)  K0 and 2K0 (C)  K0 and K0 (D) 0 and 2 K0

Tardigrade Admin · Accepted Answer

Kinctic energy + potential energy = total cnergy When kinetic energy is maximum, potential energy is zero and vice versa. ∴ Maximum potential energy = total energy. 0+K0=K0 (K.E. + P.E. = total energy).

Q. The particle executing simple harmonic motion has a kinetic energy $K_{0} cos^{2} ω t$ .The maximum values of the potential energy and the total energy are respectively

$K_{0} /2$ and $K_{0}$

$K_{0}$ and $2 K_{0}$

$K_{0}$ and $K_{0}$

$0$ and $2 K_{0}$

Kinctic energy $+$ potential energy = total cnergy When kinetic energy is maximum, potential energy is zero and vice versa.
$∴$ Maximum potential energy = total energy.
$0 + K_{0} = K_{0}$
(K.E. + P.E. = total energy).

Q. The particle executing simple harmonic motion has a kinetic energy K0​cos2ωt.The maximum values of the potential energy and the total energy are respectively

K0​/2 and K0​

K0​ and 2K0​

K0​ and K0​

0 and 2K0​