Question

The particle executing simple harmonic motion has a kinetic energy $ K_0 \cos^2 \omega t $.The maximum values of the potential energy and the total energy are respectively

• A. $ K_0 / 2 $ and $ K_0$
• B. $ K_0 $ and $ 2K_0$
• C. $ K_0 $ and $ K_0$
• D. $0$ and $ 2 K_0$

Answer 1

Answer: (C)

Kinctic energy $+$ potential energy = total cnergy When kinetic energy is maximum, potential energy is zero and vice versa.
$\therefore $ Maximum potential energy = total energy.
$0+K_{0}=K_{0}$
(K.E. + P.E. = total energy).