Question

The oxidation state of oxygen in $O_2[Pt{F}_6]$ is

• A. zero
• B. $-1/2$
• C. $+1$
• D. $+1/2$

Answer 1

Answer: (D)

$O_2[Pt{F}_6]$is considered to be formed from $O_2^{+}$ and $[Pt{F}_6{]}^{1-}$. In $O_2^{+1}$, oxidation state of $O$ is $x=+\frac{1}{2}$
$x=+\frac{1}{2}$