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  4. The oxidation state of oxygen in O2[PtF6] is

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Q. The oxidation state of oxygen in $O_{2}[PtF_{6}]$ is

Coordination Compounds

Solution:

$O_{2}[PtF_{6}] $is considered to be formed from $O^{+}_{2}$ and $[PtF_{6}]^{1-}$. In $O^{+1}_{2}$, oxidation state of $O$ is $x = + \frac{1}{2}$
$x= +\frac{1}{2}$