Question

The oxidation state of oxygen in $O_{2}Pt{F}_6$

• A. 0
• B. +1
• C. $+\frac{1}{2}$
• D. $-\frac{1}{2}$

Answer 1

Answer: (C)

In $O_2$ Pt $F_6$, the O.N. of Pt = + 5
Therefore,$2x+5-6=0$ or $2x=1$ or $x=+\frac{1}{2}$