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Q. The oxidation state of oxygen in $O_2 Pt F_6$

Redox Reactions

Solution:

In $O_2$ Pt $F_6$, the O.N. of Pt = + 5
Therefore,$ 2 x + 5 - 6 = 0 $ or $2 x = 1$ or $x = + \frac{1}{2}$