Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The oxidation state of molybdenum in its oxo complex species [Mo2O4(C2H4)2(H2O2)]2- is
Q. The oxidation state of molybdenum in its oxo complex species
[
M
o
2
O
4
(
C
2
H
4
)
2
(
H
2
O
2
)
]
2
−
is
3388
210
Redox Reactions
Report Error
A
+
2
18%
B
+
3
54%
C
+
4
22%
D
+
5
5%
Solution:
Oxidation number of
M
o
in
[
M
o
2
O
4
(
C
2
H
4
)
2
(
H
2
O
2
)
]
2
−
2
x
+
4
(
−
2
)
+
0
+
0
=
−
2
2
x
−
8
=
−
2
⇒
x
=
+
3