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  4. The oxidation state of molybdenum in its oxo complex species [Mo2O4(C2H4)2(H2O2)]2- is

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Q. The oxidation state of molybdenum in its oxo complex species $[Mo_2O_4(C_2H_4)_2(H_2O_2)]^{2-}$ is

Redox Reactions

Solution:

Oxidation number of $Mo$ in
$[Mo_2O_4(C_2H_4)_2(H_2O_2)]^{2-}$
$2x + 4(-2) + 0 + 0 = -2$
$2x - 8 = -2 \quad\Rightarrow \quad x = +3$