Question

The oxidation state of $Cr$ in $K_{2}C{r}_2{O}_7$ is

• A. $+4$
• B. $+3$
• C. $+6$
• D. $+5$

Answer 1

Answer: (C)

$K_{2}C{r}_2{O}_7$

Let the oxidation state of $Cr$ is $x$.

$2(+1)+2x+7(-2)=0$

$+2+2x-14=0$

$2x-12=0$

$x=+6$