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Chemistry
The oxidation state of Cr in K2Cr2O7 is
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Q. The oxidation state of $ Cr $ in $ K_2Cr_2O_7 $ is
MHT CET
MHT CET 2012
A
$ +4 $
B
$ +3 $
C
$ +6 $
D
$ +5 $
Solution:
$K _{ 2 } C r _{ 2 } O _{7}$
Let the oxidation state of $Cr$ is $x$.
$2(+1)+2 x+7(-2) =0 $
$+2+2 x-14 =0$
$2 x-12 =0$
$x =+6$